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2D Arrays – FRQ Practice (AP Computer Science A)

2D Arrays FRQ Practice Ap Computer Science

2D arrays appear frequently in AP Computer Science A FRQs because they test a student’s ability to traverse grids, navigate rows and columns, process neighbors, and design algorithms using nested loops.

This page provides, exam-style FRQs focused entirely on 2D array logic.

Why Practice 2D Array FRQs?

AP CSA often includes free-response questions involving:

  • Row-by-row traversal
  • Column-by-column traversal
  • Counting values in a grid
  • Searching for patterns
  • Neighbor-based calculations
  • Modifying 2D arrays
  • Nested loop logic

Mastering these skills significantly improves FRQ performance.


How to Use This FRQ Page

  • Try each problem independently first
  • Compare your approach with the provided solution
  • Study the Common Mistakes section
  • Reattempt until you can solve quickly and consistently
  • Use these as real exam warm-ups

FRQ 1 — Count Zeros in a 2D Array (Easy)

Problem:
Write a method countZeros(int[][] grid) that returns how many elements in a 2D array are equal to 0.

Example:
Input:

1 0 3
0 2 4

Output → 2

Approach:

  • Use nested loops
  • Count elements equal to zero

Java Solution:

public int countZeros(int[][] grid) {
    int count = 0;
    for (int r = 0; r < grid.length; r++) {
        for (int c = 0; c < grid[0].length; c++) {
            if (grid[r][c] == 0) {
                count++;
            }
        }
    }
    return count;
}

Common Mistakes:

  • Using grid.length for both rows and columns
  • Off-by-one errors
  • Returning premature values

FRQ 2 — Row Sum (Easy)

Problem:
Write a method sumRow(int[][] grid, int row) that returns the sum of all elements in the given row.
Assume row is valid.

Example:
Row 1 of

2 5 1
3 4 6

→ 3 + 4 + 6 = 13

Approach:

  • Loop through all columns in the specified row
  • Accumulate the sum

Java Solution:

public int sumRow(int[][] grid, int row) {
    int sum = 0;
    for (int col = 0; col < grid[row].length; col++) {
        sum += grid[row][col];
    }
    return sum;
}

Common Mistakes:

  • Using grid.length instead of grid[row].length
  • Forgetting to initialize sum
  • Handling invalid rows (not required here)

FRQ 3 — Find Maximum in the Grid (Medium)

Problem:
Write findMax(int[][] grid) that returns the largest value in the entire 2D array.

Approach:

  • Set max to first element
  • Traverse all rows and columns
  • Update when a larger value is found

Java Solution:

public int findMax(int[][] grid) {
    int max = grid[0][0];

    for (int r = 0; r < grid.length; r++) {
        for (int c = 0; c < grid[r].length; c++) {
            if (grid[r][c] > max) {
                max = grid[r][c];
            }
        }
    }
    return max;
}

Common Mistakes:

  • Using grid[0].length for every row (irregular arrays fail)
  • Forgetting to compare all cells
  • Incorrect initialization of max

FRQ 4 — Count Neighbors Greater Than a Value (Hard)

Problem:
Write a method countGreaterNeighbors(int[][] grid, int value) that returns how many cells have at least one neighbor (up/down/left/right) greater than value.

Boundary edges must be handled correctly.

Example:
If a cell has neighbor > value → count it.

Approach:

  • Traverse grid
  • For each cell, check valid neighbors
  • Count if any neighbor is > value

Java Solution:

public int countGreaterNeighbors(int[][] grid, int value) {
    int count = 0;

    for (int r = 0; r < grid.length; r++) {
        for (int c = 0; c < grid[r].length; c++) {

            boolean found = false;

            // up
            if (r > 0 && grid[r-1][c] > value) found = true;

            // down
            if (r < grid.length - 1 && grid[r+1][c] > value) found = true;

            // left
            if (c > 0 && grid[r][c-1] > value) found = true;

            // right
            if (c < grid[r].length - 1 && grid[r][c+1] > value) found = true;

            if (found) count++;
        }
    }

    return count;
}

Common Mistakes:

  • Forgetting boundary checks
  • Using OR instead of AND incorrectly
  • Counting neighbors instead of counting cells with neighbors

FRQ 5 — Create a Transposed Matrix (Hard)

Problem:
Write a method transpose(int[][] grid) that returns a new 2D array representing the transpose of the original matrix.

Transpose rule:
result[c][r] = grid[r][c]

Approach:

  • Create array of size [cols][rows]
  • Swap row/column indices when copying

Java Solution:

public int[][] transpose(int[][] grid) {
    int rows = grid.length;
    int cols = grid[0].length;

    int[][] result = new int[cols][rows];

    for (int r = 0; r < rows; r++) {
        for (int c = 0; c < cols; c++) {
            result[c][r] = grid[r][c];
        }
    }

    return result;
}

Common Mistakes:

  • Using same row/column count
  • Returning the original array
  • Incorrect index assignment

More 2D Array FRQs Coming Soon

  • Count increasing neighbors
  • Find the row with largest sum
  • Spiral traversal
  • Flood-fill style problems
  • Count isolated values

Related FRQ Pages

  • Arrays – FRQ Practice
  • ArrayList – FRQ Practice
  • Strings – FRQ Practice
  • Mixed FRQs
  • Mock FRQ Sets

(Add links once pages are published)


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